Math, asked by vansh4778, 1 year ago

If a large integers is 2 more than four times or four times and other integer and their difference is 32 find the integers

Answers

Answered by Anonymous
8

Answer:

10 and 42

Step-by-step explanation:

Let the numbers be x and y .

Large number = x

Small number = y

x - y = 32 ...... ( 1 )

x - 2 = 4 y ....... ( 2 )

Subtracting ( 2 ) from ( 1 ) we get :

- y + 2 = 32 - 4 y

= > 3 y = 32 - 2

= > 3 y = 30

= > y = 30/3

= > y = 10

The big number is 10 + 32 = 42 .

Hence your answer is 10 and 42 .

Answered by Krish008
7
let the smaller integer be x .then according to given condition another integer would be 4x + 2.

now we have, (4x + 2) -x =32

3x = 32-2=30

x= 10 and 4x +2=42 would be the required integers.

hope this will help you.
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