if a larger integer is 2 more than 4 times another integer and their difference is 32 find the integer.
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Answered by
46
let the integer be x ,
let the second integer be 4x+2 then
4x+2-x=32
3x=32-2
3x=30
x=30/3=10
then the integers will be 10(small(x)) and 42(large(4x+2))
let the second integer be 4x+2 then
4x+2-x=32
3x=32-2
3x=30
x=30/3=10
then the integers will be 10(small(x)) and 42(large(4x+2))
Answered by
9
Let large integer be x, other integer be y
From question:
x=4y+2
x-y=32
So x=42,y=10
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