Math, asked by chauhansonu2515, 1 year ago

if a lawn 30m long 16 m wide is surrounded by a path 2m wide, what is the area of the path

Answers

Answered by aayushibhimjiani
1

Answer:

Area of lawn = l*b = 30*16 = 480 m²

now new length = 30+2 = 32

new breadth = 16 +2 =18

New area = l*b = 32*18 = 576 m²

So area of path = New area - Original area = 576-480 = 96 m²

Area of path = 96 m²



aayushibhimjiani: pls mark it as brainliest
Answered by nilesh102
28

Question:-

if a lawn 30m long 16 m wide is surrounded by a path 2m wide, what is the area of the path

solution:-

Let, L be the length of rectangle and B be the breadth rectangle.

By Question:-

We know formula of

=> Area of rectangle = L × B

=> Area of rectangle = 30 × 16

=> Area of rectangle = 480 m²

=> X = 480

we know that length and breadth increase by 2 m from their both ends.

so,

=> L = 30 + 2 + 2 = 34 m.

=> B = 16 + 2 + 2 = 20 m.

We know formula of

=> Area of rectangle + path = L × B

=> Area of rectangle + path

= 34 × 20

=> Area of rectangle + path

= 680 m²

=> Z = 680

=> Area of path =( Z ) - ( X )

=> Area of path = 680 - 480

=> Area of path = 200 m²

Area of path 200 m².

i hope it helps you.

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