if a lawn 30m long 16 m wide is surrounded by a path 2m wide, what is the area of the path
Answers
Answer:
Area of lawn = l*b = 30*16 = 480 m²
now new length = 30+2 = 32
new breadth = 16 +2 =18
New area = l*b = 32*18 = 576 m²
So area of path = New area - Original area = 576-480 = 96 m²
Area of path = 96 m²
Question:-
if a lawn 30m long 16 m wide is surrounded by a path 2m wide, what is the area of the path
solution:-
Let, L be the length of rectangle and B be the breadth rectangle.
By Question:-
We know formula of
=> Area of rectangle = L × B
=> Area of rectangle = 30 × 16
=> Area of rectangle = 480 m²
=> X = 480 m²
we know that length and breadth increase by 2 m from their both ends.
so,
=> L = 30 + 2 + 2 = 34 m.
=> B = 16 + 2 + 2 = 20 m.
We know formula of
=> Area of rectangle + path = L × B
=> Area of rectangle + path
= 34 × 20
=> Area of rectangle + path
= 680 m²
=> Z = 680 m²
=> Area of path =( Z ) - ( X )
=> Area of path = 680 - 480
=> Area of path = 200 m²
Area of path 200 m².
i hope it helps you.