Question

If a leap year is selected at random what is the chance that it will contain 53 tuesdays

Answer 1

Number of days in a leap year= 366 days

There are 366 days in a leap year that contain 52 weeks and 2 more days. So, 52 Tuesdays and 2 days.

These 2 days can be:
(Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat, Sun} and {Sun, Mon} (7 cases). 

In order to have 53 Tuesdays we should have either {Mon,Tues} or {Tues, wed} case. 

No. of sample spaces = 7.

No. of event that gives 53 Tuesdays in Leap Year = 2.

Required Probability = 2/7

Hope this will help you....

Answer 2

A leap year generally contains 52weeks and 2 days.
so last 2 days may be
monday and Tuesday
Tuesday and Wednesday
Wednesday and Thursday
Thursday and Friday
Friday and Saturday
Saturday and Sunday
or Sunday and Monday

Here Tuesday comes 2 times out of 7 outcomes....

So the probability of 53 Tuesdays in a leap year is 2/7

HOPE IT HELPS.....