If a lever is used to lift a load with a resistance force of 500 N. The load is 1 m from the fulcrum. How far from the fulcrum must an effort force of 250 N be applied to lift the load?
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f=500N
distance=1m
WD=500J
F'=250
half of 500...so 50 cm should be the answer
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distance=1m
WD=500J
F'=250
half of 500...so 50 cm should be the answer
hope it helps you
follow me
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