if a lie in the second quarterant and 3tanA+4=0
Answers
Answered by
0
Answer:
3tanA+4=0⇒tanA=−
3
4
=
b
p
⇒p=4x,b=3x⇒h=
p
2
+b
2
=±5x
As A is in II quadrant
sinA=
5
4
and cosA=−
5
3
Therefor
2cotA−5cosA+sinA=−2.
4
3
−5(−
5
3
)+
5
4
=
10/
23
Answered by
0
Answer:
Step-by-step explanation:
3 tan A + 4 = 0
3 tan A = - 4
tan A = - 4/3
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