Question

If a light is emitted by a single source passes through two narrow slits 1.00 mm apart.
The interefence pattern is obsereved on a screen 200 cm away and the separation
between the centres of adjacent bright fringes is 2.00 mm. What would be the
wavelength of the light?
C) 2 pm
A) 2 um
D) 1 pm
B) 1 nm
Explain this kindly

Answer 1

ANSWER :-

WAVELENGTH = 2 μ m

OPTION B

EXPLANATION :-

★ WAVE OPTICS ★

★ GIVEN ;

» SLIT WIDTH ( d ) = 1 mm

» Distance between Slits and Screen ( D ) = 200 cm ≈ 2 m

» Distance between Bright Fringes ( Y ) = 2 mm

» No. of Bright Fringes = 1

★ Wavelength ( lambda ) = ???

________[ BY USING FORMULA ] ______

[ $y \: = \:( \frac{n \: \times \: lambda \: \times d \: }{d} )$ ]

★ Lambda = [ Y × d ] / n × D

» lambda = [ 2 × 10-³ × 10-³ ] / 1 × 2

» lambda = [ 2 × 10^-6 ] / 2

★ ⏩ Wavelength ( lambda ) = 2 μm ★ ⏪

_____________________________________

ANSWER :- HENCE ; Wavelength of Light having Interference pattern at screen is ;

♣ LAMBDA = 2 MICRO METRE OR 2 μm ♥