If a light ray incident on one of the faces
of the prism of refractive index 1.414
with grazing incidence and after
refraction the emergent ray just grazes
the second surface of the prism, then the
angle of deviation is
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Given:
A light ray incident on one of the faces of the prism of refractive index 1.414 with grazing incidence and after refraction the emergent ray just grazes the second surface of the prism.
To find:
The angle of deviation is?
Solution:
From given, we have,
The refractive index of the prism is 1.414.
For a total internal reflection to take place the refractive index (r)min should be greater than C and for (r2)min, r1 should be maximum, so we have, C = 45°.
The angle of deviation = 2C = 2 × 45° = 90°
Therefore, the angle of deviation is 90°
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