If a line A is parallel to line y = 3x - 6 and it cuts the y-axis at point (0, 4), then the equation of the line is:
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Answer:
y=-3x-14
Explanation:
Any line parallel to y=-3x+6
will be in the form y=-3x+c for some constant c
If (x,y)=(-3,-5) is a solution to such an equation, then replacing y with (-5) and x with (-3) gives
-5=(-3) *(-3)+c
rarr -5=9+c
rarr c=-14
So the desired parallel line would have the equation
y=-3x-14
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