If a line intersect two concentric circle (circle with the same centre) O at A, B, Cand D. prove that AB = CD.
Attachments:
Answers
Answered by
5
Answer:
ANSWER
We know that, OA=OD and OB=OC.
We know that, OA=OD and OB=OC. They are radius of respective circles.
In ΔOBC, we know that OB=OC, so ∠OBC=∠OCB
n ΔOBC, we know that OB=OC, so ∠OBC=∠OCB∴∠OCD=∠OBA
In ΔOAD, we know that OA=OD, so ∠OAD=∠ODA
In ΔOAD, we know that OA=OD, so ∠OAD=∠ODASince, ∠OCD=∠OBA and ∠OAD=∠ODA, we get ∠AOB in ΔOAB is equal to ∠COD in ΔOCD.
In ΔOAD, we know that OA=OD, so ∠OAD=∠ODASince, ∠OCD=∠OBA and ∠OAD=∠ODA, we get ∠AOB in ΔOAB is equal to ∠COD in ΔOCD.∴ From SAS congruency, we can say that ΔOAB and ΔOCD are congruent.
So, AB=CD (by CPCT).
Similar questions