Question

If a line intersects AB and AC of
La AABC at Dond E respectively and
is parallel to BC, prove that AO AE
AB
AC​

Answer 1

Answer:

Proved

Step-by-step explanation:

If a line intersects sides AB and AC of a triangle ABC at D and E respectively and is parallel to BC, prove that AD/AB=AE/AC.

DE ║ BC

in ΔABC & ΔADE

∠A = ∠A  Common Angle

∠ADE = ∠ABC   as BC ║ DE

∠AED = ∠ACB  as BC ║ DE

All three angles are equal

so

ΔABC ≅ ΔADE

in similar triangles

AD/AB =AE/AC = DE/BC

=> AD/AB =AE/AC

QED

Answer 2

Answer:

hope it helps u!!

Step-by-step explanation:

If a line intersects sides AB and AC of a triangle ABC at D and E respectively and is parallel to BC, prove that AD/AB=AE/AC.

DE ║ BC

in ΔABC & ΔADE

∠A = ∠A  Common Angle

∠ADE = ∠ABC   as BC ║ DE

∠AED = ∠ACB  as BC ║ DE

All three angles are equal

so

ΔABC ≅ ΔADE

in similar triangles

AD/AB =AE/AC = DE/BC

=> AD/AB =AE/AC

QED

pls mark me as brainiest!!:)