If a line intersects intersected 2003 the circles circles with the same Centre with Centre O at a b c and d prove that AB equal CD
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Step-by-step explanation:
OM ⊥ AD is drawn from O.
OM bisects AD as OM ⊥ AD.
⇒ AM = MD --- (i)
also, OM bisects BC as OM ⊥ BC.
⇒ BM = MC --- (ii)
From (i) and (ii),
AM - BM = MD - MC
⇒ AB = CD
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