If a line intersects two concentric circles with centre O at A,B,C & D,then prove that AB=CD
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Step-by-step explanation:
Join points O with B, A, C,D
Let the mid point of line BC = E
Join points O and E
In triangle OBE and triangle OEC,
1) OE=OE(Common)
2)OB=OC( Radii of the same circle)
3)BE=EC( Since E is the mid point of line BC)
Therefore, triangle OBE is congruent to triangle OEC
In triangle OAE and triangle OED
1)OE=OE( Common)
2)OA=OD( Radii of the same circle)
3) AE = ED( Since E is the mid point of AD)
Therefore triangle OAE is congruent to triangle OED
AB+BE=EC+CD
AB+BE=BE+CD(Since BE=CE)
Therefore AB=CD
PROVED
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