Question

If a line is drawn parallel to one side of a triangle to intersect the other two sides in

distinct points, the other two sides are divided in the same ratio.​

Answer 1

Step-by-step explanation:

Given:

DE∣∣BC

To prove that:

AE/EC=AD/BD

Proof:

∠AED=∠ACB Corresponding angles

∠ADE=∠ABC Corresponding angles

∠EAD is common to both the triangles

⇒ΔAED∼ΔACB by AAA similarity

= AC/AE=AB/AD

=AE+EC/AE =AD+BD/AD

So,. EC/AE=BD/AD

Thank you