if a line passes through (2,2) and is perpendicular to the line 3x+y=3 then find its equation of line?
deepajothi02:
pls bros' and sis pls help me...I am new here
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Good Morning!!
Equation of line perpendicular to the given line is x - 3y + k = 0
x = 2 and y = 2 becoz it's given that this line passes through the point ( 2 , 2 )
2 - 3 ( 2 ) + k = 0
k = 4
so, equation of line perpendicular to the given line is x - 3y + 4 = 0
Have a nice day ahead .
Equation of line perpendicular to the given line is x - 3y + k = 0
x = 2 and y = 2 becoz it's given that this line passes through the point ( 2 , 2 )
2 - 3 ( 2 ) + k = 0
k = 4
so, equation of line perpendicular to the given line is x - 3y + 4 = 0
Have a nice day ahead .
sure sis.
ok ..then ,I need to get ready to school,then chat later...
ok...have a nice day....
another question bro!!
the perpendicular from the origin to a line meets it at the point (-3,5),find the equation o the line
equation of line is......y - 5 = -3 / 5 ( x + 3)............
5y + 3x -16=0
tq bro ..
bye...
byy..... take care.
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