Math, asked by shashankg7145, 11 months ago

If a line-segment AB is a chord of a circle with centre O, then ΔOAB is always ____
(a) acute angled triangle
(b) equilateral triangle
(c) obtuse angled triangle
(d) isosceles triangle

Answers

Answered by archi58
0

Answer:

equilateral triangle

Step-by-step explanation:

In triangle OAB OA =OB=AB

Answered by Agastya0606
0

Answer:

If there is a line segment AB , which is a chord of a circle, joins with the centre O of the circle, then it will form:

d) isosceles triangle.

The triangle OAB is will be an isosceles triangle because , OA and OB are two radii of that circle.

Chord is a line segment passing through the circle, and radius is the half of diameter.

So, two radii will have equal length and AB has different length. Therefore according to the definition of isosceles triangle it is a triangle having two equal sides and one unequal side. So triangle OAB is isosceles triangle.

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