Question

If a line segment AB is to be divided in the ratio 5:8 internally, we draw a ray AX such

that ∠BAX is an acute angle. What will be the minimum number of points to be

located at equal distances on ray AX?
pls give answer fast​

Answer 1

13 points are required  To divide a line segment AB in the ratio 5:8

Step-by-step explanation:

To divide a line segment AB in the ratio 5:8,

Step1 : Draw a line segment AB  of some length

Step 2 :  Draw a line segment AX such that ∠BAX is an acute angle

Step 3:  Take 13 point on AX of Equal length one by one ( consecutively)

Step 4 :  Join 13th Point with B as a straight line

Step 5 : Draw a line parallel to line drawn in step 4 such that it passes through 5th point of step 3 and intersect AB at M

M divides AB in to  5 : 8 Ratio.

13 points are required

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