Question

If a line segment AB is to be divided in the ratio 5:8 internally. we draw a ray AX such that angle BAX is an acute angle. What will be
the minimum number of points to be located at equal distance on ray Ax ?
draw with all construction .​

Answer 1

Answer:

Step-by-step explanation:

1. At A make ∠BAX any acute angle

2. Cut AX=13 cm and join BX

3. On AX cut AC=5 cm so CX=8 cm

4. From  C draw CP || BX ( By making ∠ACP =∠AXB)

5.You will find AP:PB=5:8