Math, asked by itrack693, 1 month ago

If a line segment AB is to be divided in the ratio 5:8 internally we draw a ray AX such that angle BAX is an acute angle what will be the minimum number of point to be located at equal distance on ray AX​

Answers

Answered by nithish121
4

Answer:

the minimum number of point to be located at equal distance on ray AX is 5

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