If a line through one vertex of a triangle divides opposite side in the ratio of other two sides then the line bisect the angle at the vertex D is a point on side BC such that BD upon CD is equal to AB Upon AC prove D bisects angle BAC
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skkhan0786:
thank you very much good work
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let us just draw an triangle
Step-by-step explanation:
so <1=<2
then d bisects angle bac
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