Question

If a linear equation passes through the points (3, –3) and (5, –6) then write the equation

of the line




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Answer 1

Answer:

l : 3x + 2y - 3

Step-by-step explanation:

Given points A(3,-3) and B(5,-6)

x1 = 3    y1 = -3

x2 = 5   y2 = -6

Using two-point form of line :

$\frac{x-x1}{y-y1} = \frac{x2-x1}{y2-y1}$

so, equation of line :  $\frac{x-3}{y-(-3)} = \frac{5-3}{(-6)-(-3)}$

(x-3) (-6+3) = (y+3) (2)

-3(x-3) = 2(y+3)

-3x + 9 = 2y + 6

so we get, line l : 3x + 2y - 3