If a lines drawn paralel the one of a triangle to inrrset the to rides in distincet point the other to rides are dividecil in the same ratio
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Step-by-step explanation:
If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points , then the other two sides are divided in the same ratio. Given: In ∆ABC , which intersects AB and AC at D and F respectively.
Given:
DE∣∣BC
To prove that:
AE
EC
=
AD
BD
Proof:
∠AED=∠ACB Corresponding angles
∠ADE=∠ABC Corresponding angles
∠EAD is common to both the triangles
⇒ΔAED∼ΔACB by AAA similarity
⇒
AE
AC
=
AD
AB
⇒
AE
AE+EC
=
AD
AD+BD
⇒
AE
EC
=
AD
BD
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