Question

If a liquid of specific gravity 1 rises to a height of 2.5cm in capillary tube then another liquid of specific gravity 1.25 will rise to height in the same tube is?​

Answer 1

Answer:

2 cm

Explanation:

Formula:-

Formula:-h=2Tcos thetha/reg

Formula:-h=2Tcos thetha/regh inversely proportional to 1/s

Formula:-h=2Tcos thetha/regh inversely proportional to 1/sh1s1=h2s2

$sp \: g = \frac{d}{dw}$

2s×1×dw=h2×1.25× dw

h2=2.5/1.25

h2=2 cm

Therefore,answer is 2cm