Math, asked by panchalraj558pdr62s, 1 year ago

If a load F 1200 kg is lifted an effort of 300 kg by a simple machine having velocity ratio of 5, then it's efficiency is -

Answers

Answered by sivagovindharao
15
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panchalraj558pdr62s: option is A)80%, B)75%, C)70%,D)65.
sivagovindharao: kqow91919293 isiis
Answered by KrystaCort
5

Answer:

80%

Step-by-step explanation:

The formula used for Mechanical Advantage is:

\text{Mechanical Advantage}= \frac{\text{Load}}{\text{Effort}}

= \frac{1200}{300}

= 400

Also, Velocity Ratio = 5

Efficiency is calculate by:

\text{Efficiency}= \frac{\text{Mechanical Advantage}}{\text{velocity ratio}}

= \frac{400}{5}

= 80

Hence, Efficiency = 80%

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