If a=log12 base 24,b=log24 base 36,c=log 36 base 48,Then show thatIf a=log12 base 24,b=log24 base 36,c=log 36 base 48,Then bc(2-a)
Answers
Answered by
1
Answer:
abc=(log_24 12)*(log_36 24)*(log_48 36)
=(log12/log24)*(log24/log36)*(log36/log48)
log12/log48
=(log4+log3)/(log16+log3)
=(2+x)/(4+x)
1+abc=2*(x+3)/(x+4)
where x=(log_2 3)
Step-by-step explanation:
mark me as brainliest please.....
Similar questions