Question

If a=log12 base 24,b=log24 base 36,c=log 36 base 48,Then show thatIf a=log12 base 24,b=log24 base 36,c=log 36 base 48,Then bc(2-a)

Answer 1

Answer:

abc=(log_24 12)*(log_36 24)*(log_48 36)

=(log12/log24)*(log24/log36)*(log36/log48)

log12/log48

=(log4+log3)/(log16+log3)

=(2+x)/(4+x)

1+abc=2*(x+3)/(x+4)

where x=(log_2 3)

Step-by-step explanation:

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