Question

if a = log20, b= log 8/3 and c=2 log √3/2 find a-b-c

Answer 1

$\mathfrak{ANSWER}$



$a = log(20) \\ b = log( \frac{8}{3} ) \\ c = 2 log( \frac{ \sqrt{3} }{2} ) \\ \\ \\ a - b - c \\ \\ \\ = log(20) - log( \frac{8}{3} ) - 2 log( \frac{ \sqrt{3} }{2} ) \\ \\ \\ = log(20) - log( \frac{8}{3} ) - log( { \frac{( \sqrt{3} }{2} })^{2} ) \\ \\ \\ = log(20 \div \frac{8}{3} \div \frac{3}{4} ) \\ \\ \\ = log(20 \times \frac{3}{8} \times \frac{4}{3} ) \\ \\ \\ = log(10) \\ \\ \\ = 1$


$\bold{\boxed{SOLUTION=1}}$


[ NOTE :- Rules used :-

$log( \alpha ) - log( \beta ) = log( \alpha \div \beta ) \\ \\ \\ log(10) = 1$
]

Answer 2

Step-by-step explanation:

this is correct answer