Question

If a = log24 12,b = log36 24 and c = log18 36, then 1+ abc is equal to
(a) 2ab
(b) 2ac
© 2bc
(d) 0​

Answer 1

Answer:

2AB is the answer of the given question

Answer 2

$\large\underline\mathrm\red{Solution}$

$\large\mathrm{a = log24 12}$

$\large\mathrm{24^a = 12}$

$\large\mathrm\red{Putting \: the \: both \: side \: of \: log, \: we \: get}$

$\large\mathrm{log24^a = log12}$

$\large\mathrm{alog24 = log12}$

$\large\mathrm{a = log12/log24}$

$\large\mathrm\red{Now}$,

$\large\mathrm{b = log24/log36}$

$\large\mathrm{c = log36/log48}$

$\large\mathrm{abc \: = log12/log24 . log24/log36 . log36/log48}$

$\large\underline\mathrm{log12/log48}$

$\large\mathrm{1 + abc = log48 + log12 / log48}$

$\large\mathrm{log(48.12) / log48}$

$\large\mathrm{log24²/log48}$

$\large\mathrm{2.log24/log48}$

$\large\mathrm{2bc}$

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