Question

If a = log24 12, b = log36 24, c = log48 36. Then 1 + abc is equal to

Answer 1

abc=(log_24 12)*(log_36 24)*(log_48 36)

      =(log12/log24)*(log24/log36)*(log36/log48)

      log12/log48

    =(log4+log3)/(log16+log3)

     =(2+x)/(4+x)

1+abc=2*(x+3)/(x+4)

where x=(log_2 3)