Question

If a long rope of length
(v3 - 18y2 - 40y) m is
cut into equal ropes of
length (y + 2) m each,
find the number of
smaller ropes obtained.​

Answer 1

Answer:

y (y-20)

Step-by-step explanation:

(y3-18y2-40y)/(y+2)= y (y2-18 y-40)/(y+2)

=y(y2-20y + 2y -40)/(y+2)

=y [y(y-20) + 2 (y-20)]/(y+2)

= y (y-20)(y+2)/(y+2)

=y (y-20)

Answer 2

Answer:

Step-by-step explanation:

(y3-18y2-40y)/(y+2)= y (y2-18 y-40)/(y+2)

=y(y2-20y + 2y -40)/(y+2)

=y [y(y-20) + 2 (y-20)]/(y+2)

= y (y-20)(y+2)/(y+2)

=y (y-20)

thnx