If a < 0, c > 0 and b = 0 for the quadratic equation ax2 – bx – c = 0, then the equation has
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Answer:
x= +- √(-c/a)
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Since, a,b,c>0 and ax
2 +bx+c=0 then,
⇒ x= 2a−b± 2ab −4ac
Case1: When b 2−4ac>0
⇒ x= 2a−b − 2ab −4ac
and 2a−b + 2ab 2−4ac
both roots are negatie.
Case when−4ac=0
⇒ x= 2a−b
i.e., both roots are equal and negative.
have negative real part.
∴ From above discission both roots have negative real parts.
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