Question

if a<0 then a+1/a is
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Answer 1

if a > 0 and 1/a <= 0

if a > 0 and 1/a <= 0then 1= a*(1/a) <= a*0 =0.

if a > 0 and 1/a <= 0then 1= a*(1/a) <= a*0 =0.assume a>0 and 1/a <= 0.

if a > 0 and 1/a <= 0then 1= a*(1/a) <= a*0 =0.assume a>0 and 1/a <= 0.then 1/a = [a(1/a)] / a <= 0.

if a > 0 and 1/a <= 0then 1= a*(1/a) <= a*0 =0.assume a>0 and 1/a <= 0.then 1/a = [a(1/a)] / a <= 0.so a*(1/a) <= 0. (multiplying both sides by a)

if a > 0 and 1/a <= 0then 1= a*(1/a) <= a*0 =0.assume a>0 and 1/a <= 0.then 1/a = [a(1/a)] / a <= 0.so a*(1/a) <= 0. (multiplying both sides by a)but this contradicts our assumption that a > 0. (since a* 1/a is assumed greater than 0.)

if a > 0 and 1/a <= 0then 1= a*(1/a) <= a*0 =0.assume a>0 and 1/a <= 0.then 1/a = [a(1/a)] / a <= 0.so a*(1/a) <= 0. (multiplying both sides by a)but this contradicts our assumption that a > 0. (since a* 1/a is assumed greater than 0.)Therefore, 1/a > 0.