Question

if a<b<2a and the median and the mean of a,b and 2a are 15 and 12 respectively then​

Answer 1

Answer:

11

Step-by-step explanation:

Given, a,b,2a. i.ei. n = 3.

Median = [(N+1)/2]th term

= [(3+1)/2]th  

= 4/2nd

= 2nd term.

2nd term is B.

so b = 12.

Mean = Ex/N

= (a + b + 2a) / 3 = 15

Taking LHS denominator (3) to RHS,we get,

3a + 12 = 15 * 3

3a + 12 = 45

3a = 45-12

3a = 33

a = 33/3

a=11

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