If a +
= m and a = 0; find in terms of 'm': the
value of
1
(i) a
(ii) a2
1
a 2
Answers
Answered by
0
Answer:
a+
a
1
=m
Squaring both sides,
=(a+
a
1
)
2
=m
2
=a
2
+(
a
1
)
2
+2(a)(
a
1
)=m
2
=a
2
+
a
2
1
+2=m
2
=a
2
+
a
2
1
=m
2
−2
Now,
(a−
a
1
)
2
=a
2
+
a
2
1
−2(a)(
a
1
)
=m
2
−2−2
=m
2
−4
=>a−
a
1
=±
m
2
−4
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