Question

If a +
= m and a = 0; find in terms of 'm': the
value of
1
(i) a
(ii) a2
1
a 2​

Answer 1

Answer:

a+

a

1

=m

Squaring both sides,

=(a+

a

1

)

2

=m

2

=a

2

+(

a

1

)

2

+2(a)(

a

1

)=m

2

=a

2

+

a

2

1

+2=m

2

=a

2

+

a

2

1

=m

2

−2

Now,

(a−

a

1

)

2

=a

2

+

a

2

1

−2(a)(

a

1

)

=m

2

−2−2

=m

2

−4

=>a−

a

1

=±

m

2

−4