If a magnet is suspended at an angle 30 to the magnetic meridian
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Step-by-step explanation:
Answer:
Real dip
θ
=
40.9
∘
Explanation:
Let the vertical component of earth's magnetic field be V and its horizontal component at magnetic meridian be H.
Then the angle of dip
θ
at magnetic meridian will be given by
tan
θ
=
V
H
...
...
[
1
]
When the dip needle is suspended at an angle of
30
∘
to the earth magnetic meridian then it makes an angle
45
∘
with the horizontal.
In this situation vertical component of earth's field responsible for its orientation with the horizontal direction, remains same as
V
but the component in horizontal direction becomes
H
cos
30
∘
So
tan
45
∘
=
V
H
cos
30
∘
⇒
V
H
=
cos
30
∘
...
...
.
[
2
]
Comparing [1] and [2] we get
tan
θ
=
cos
30
∘
=
√
3
2
⇒
θ
=
tan
−
1
(
√
3
2
)
≈
40.9
∘
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