Question

If a magnet is suspended at an angle of 30 degree to magnetic meridian, the dip needle makes an angle of 45 degree with the horizontal. The real dip is

Answer 1

Answer:

40.89 degree.

Explanation:

Since, from the question we get that the magnet is suspended at the angle of 30 degree to the magnetic meridian so the horizontal component or the apparent horizontal component will be Bh' =Bhcosθ. Where θ is 30 degree.

Now, Bh' = √3/2Bh.

Again, the angle of dip δ is tanδ= Bv/Bh' or tanδ=2/Bh√3.

since, the angle of dip δ is given in the question as 45 degree so, tan45=2/Bh√3 which on solving we will get the value of δ to be 40.89 degree.

Answer 2

Answer:

ur answer is 40.89