If a man complete a work in 2 months 10 days, how much time will be taken to complete the same work by 7 man?solution fast
Answers
Answered by
0
Answer:
2 months + 10 days => 30 + 31 + 10 = 71 days
work done by 1 man — 71 days
work done by 7 man — 71÷7 = 10.5 days
Answered by
0
Answer:
10 days
Step-by-step explanation:
simply use unitary method,
work done by 1 man in 1 day = 1/2 months 10 days = 1/70
work done by 7 man in 1 day = (1/70)*7 = 1/10
now, we know 7 man do one tenth of the whole work in 1 day so to complete the whole work by 7 man = 10 days
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