Chemistry, asked by Lillipop, 11 months ago

If a man cycles at 10 km/hr, then he arrives at a certain place at 1 PM. If he cycles at 15 km/hr, he will arrive at the same place at 11 AM. At what speed must he cycle to get there at noon?

11 km/hr
12 km/hr
13 km/hr
14 km/hr

Answers

Answered by Anonymous
2

Answer:

The correct option is B.

Explanation:

When speed of the man = 10 km/hr = d/t

When speed of the man = 15 km/hr = d/(t-2)

Equating the value of d,

10 × t = 15 × (t - 2)

t = 6 hours.

Desired speed = d/(t-1) = 10t/(t-1) = 12

Answered by Bhola122
0

Answer:

Explanation:

If a man cycles at 10 km/hr, then he arrives at a certain place at 1 PM. If he cycles at 15 km/hr, he will arrive at the same place at 11 AM. At what speed must he cycle to get there at noon?

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