if a man has to buy 100 animals with 100 dollar cost of 1 peacock is $ 7
cost of 8 monkey is $ 3
cost of 3 fox is $ 4 what is the number of each animal ?
Answers
Answer:
Ans: 1 cow + 19 buffalo + 80 goats
This is fun! Thanks for the A2A
Ok so you have 2 equations with 3 variables which initially appears to be insufficient information however since (im assuming) you are restricted to whole numbers for animals (unless you want to buy living animals) there should be a finite number of solutions here.
1 cow = 1 Rupees
1 buffalo = 5 Rupees
1 goat = 0.05 Rupees
If you buy all cows you will spend 100 rupees on 100 animals but you will not have all 3 types.
If i swap out 5 rupees worth of cows for 5 rupees worth of buffalos i will have 4 less animals, and still spend all the money.
If i swap out 1 rupees worth of cows for 1 rupees worth of goats, i will have gained 19 animals, and still spend all the money.
The lowest common denominator between 4 and 19 is 76, so if I gain 76 animals by swapping out 4 rupees worth of cows for goats, and I lose 76 animals by swapping out 95 rupees worth of cows for buffalos, i will have the following:
1 cow, 19 buffalo, 80 goats
Proceeding to the next iterative answer (19 more buffalo, 80 more goats) would yield a negative amount of cows (-98 cows) which means this is the only answer.