Question

If a man increased his speed by 2 m/s his kinetic energy is doubled the original speed of man is

Answer 1

Answer:

Explanation:

$k=\frac{1}{2}mv^{2}$  (ii)

v+2;then kinetic energy =2k

$2k=\frac{1}{2}m(v+2)^{2}$  (i)

dividing (ii)by(i)

$\frac{2k}{k}=\frac{0.5m(v+2)^{2} }{0.5mv^{2} }$

solve and get answer