Question

If a man lost 4% by selling oranges at the rate of 12 a rupee at how many a rupee must he sell them to gain 44%?​

Answer 1

Answer:

Given:

⇏ If a man lost 4% by selling oranges at the rate of 12 a rupee.

Find:

⇏ How many rupees he must sell them to gain 44%?

According to the question:

⇏ 12 = 96% cost of a orange.

Know terms:

⇏ (CI) = Cost price.

⇏ (SI) = Simple interest.

Calculations:

⇏ $\sf 100\% = \dfrac{12}{96} \times 100 = \dfrac{100}{8}$

⇏ $\sf CP = 1 \: orange = \dfrac{100}{8}$

⇏ $\sf SP = orange \: for \: gain \: 44\%$

⇏ $\sf \dfrac{100}{8} + 44\% = \dfrac{100}{8}$

⇏ $\sf \dfrac{100}{8} + \dfrac{44}{8}$

⇏ $\sf \dfrac{144}{8}$

⇏ $\sf\boxed{ 18}$

Therefore, he must sell rupees 18 a orange to gain 44%.

Answer 2

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QUESTION :

If a man lost 4% by selling oranges at the rate of 12 a rupee at how many a rupee must he sell them to gain 44%?..

SOLUTION :

In the above Question, the following information is given :

A man lost 4% by selling oranges at the rate of 12 a rupee.

Let the original cost price of each orange be Rs. X

=> 96 % of X = 12

=> X = Rs. 100 / 8 = Rs. 12.5

Now, he has to gain 44 %

So, new SP = 144 % of X

=> 144 % of 12.5

=> 144 × 125 / 1000

=> Rs. 18

So, the new SP is Rs. 18

ANSWER :

He should sell the oranges at a rate of 18 per rupee to gain 44%.