Question

If a man moving towards right exerts a normal force of 100N on the ground and statuc coefficient of friction in 0.3 and kinematic coefficient of friction is 0.2 then the frictional force exerted on the mans feet bu ground is

Answer 1

Answer:

76 feet ground is the correct answer

Answer 2

Answer:

The frictional force exerted on the man's feet is 20N.

Explanation:

Given:

N = 100N

u = 0.2

The friction that is exerted on man's feet is kinematic friction because man is in motion.

Here,

The normal force is denoted by N.

The kinematic coefficient is denoted by u.

The frictional force is denoted by F.

Then,

By the equation,

F = uN

F = 0.2 × 100

F = 20N

So, the frictional force exerted on the man's feet is 20N.