if a man of mass M jumps to the ground from a height h and it's centre of mass moves a distance X in the average time taken by him to hit the ground the average force acting on him (assuming his retardation to be constant during his impact with the ground)is
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Answer:
workdone=change in potential energy
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Answer:
mgh/x
Explanation:
force = change in potential energy / position
force = mgh/x
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