Math, asked by ItzMissLegend, 8 hours ago

If a man reduces the selling price of a fan from Rs 400 to 300, his loss increased by 40% . What is the Cost Price of fan ?​

Answers

Answered by Anonymous
1

Answer:

Let the C.P. = Rs. x.

Then First loss % = (x−400)/x × 100= (100x−40000)/x %

Second loss % = (x−380)/x × 100= (100x−38000)/x %

Given, (100x−38000)/x − (100x−40000)/ = 40

⇒100x−38000−100x+40000=40x

⇒2000=40x

⇒x=50

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Answered by ShaanDutta703
1

Let the C.P. = Rs. x.

Then First loss % =

x

(x−400)

×100=

x

100x−40000

%

Second loss % =

x

(x−380)

×100=

x

100x−38000

%

Given,

x

(100x−38000)

x

(100x−40000)

=4

⇒100x−38000−100x+40000=4x

⇒2000=4x

⇒x=500

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