If a man reduces the selling price of a fan from Rs 400 to 300, his loss increased by 40% . What is the Cost Price of fan ?
Answers
Answered by
1
Answer:
Let the C.P. = Rs. x.
Then First loss % = (x−400)/x × 100= (100x−40000)/x %
Second loss % = (x−380)/x × 100= (100x−38000)/x %
Given, (100x−38000)/x − (100x−40000)/ = 40
⇒100x−38000−100x+40000=40x
⇒2000=40x
⇒x=50
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Answered by
1
Let the C.P. = Rs. x.
Then First loss % =
x
(x−400)
×100=
x
100x−40000
%
Second loss % =
x
(x−380)
×100=
x
100x−38000
%
Given,
x
(100x−38000)
−
x
(100x−40000)
=4
⇒100x−38000−100x+40000=4x
⇒2000=4x
⇒x=500
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