Question

If a man throw a ball up to a max horizontal distance of 40m, the max height attained by the ball will be ?

Answer 1

Answer:

From the given maximum vertical distance h = 40 m,

initial speed is calculated using "v2 = u2 - 2 g h " , assuming final speed v = 0 .  

 

initial speed, u = begin mathsize 12px style square root of 2 space g space h end root space equals space square root of 2 cross times 9.8 cross times 40 space end root space equals space 28 space m divided by s end style

Horizontal direction, maximum range is obtained when the projection angle with horizontal is 45º.

 

Range for projectile motion, R = (u2×sin2α) / g  , if α = 45º, R = (28×28)/9.8 = 80 m