if a man travel 300 distance in 2.5 m and then after same man back on 100 m in 1 min in the same road then what is velocity of that man
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here the total path=300meter
time taken to cover this path=2.5minut ,so
speed=300meter/2.5×60second
=5/2.5
=2m/s
he return back 100m,
time taken=1m
speed=100/60
=1.66s
displacement =300-100
=200
remaining time =2.5minut-1minut
=1.5minut
velocity=displacement/time
=200/1.5
=133.33m/S. (ans)
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