Question

if a man travel 300 distance in 2.5 m and then after same man back on 100 m in 1 min in the same road then what is velocity of that man​

Answer 1

Answer:

here the total path=300meter

time taken to cover this path=2.5minut ,so

speed=300meter/2.5×60second

=5/2.5

=2m/s

he return back 100m,

time taken=1m

speed=100/60

=1.66s

displacement =300-100

=200

remaining time =2.5minut-1minut

=1.5minut

velocity=displacement/time

=200/1.5

=133.33m/S. (ans)