Question

If a man travel at a speed of 30km/hr ,he reaches his distancetion 10 minutes late and if he travels at a speed of 42km/hr, he reaches his distination 10 minutes early . The distance travelled is

Answer 1

hope it helps you very complicated question

Answer 2

answer: -70km ( backwards)

Step-by-step explanation:

speed= distance

time

*30km/hr= x (+ 10)

y

#40km/hr= x (- 10)

y

substitution method:

*30y= x + 10

30y - 10= x

#40y = (30y - 10) - 10

40y = 30y - 10- 10

40y = 30y - 20

40y - 30y = -20

10y = -20

-20/ 10

y= -2

*30(-2) - 10= x

-60 - 10 = -70

x= -70

answer= -70 ( backwards)

*sorry if am wrong please correct me*