Question

if a man travel at a speed of 30km per hour he reaches his destination 10 minutes late and if he travels at a speed of 42km per hour he reaches his destination 10 minutes early. the distance travelled is ​

Answer 1

24 kph=.4 k/minute

30 kph=.5 k/minute

Let n be the distance to the destination. Then:

n/.4 -5=n/.5 +4

n/.4=n/.5 +9

5n=4n+18

n=18km

Answer 2

Answer:

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Step-by-step explanation:

If a person travelling between two points reaches p hrs late travelling at u kmph and reaches q hrs early travelling at v kmph,then distance is given as:

D=[(p+q) *v* u]/ (v-u)

p= 5 min=1/12 hr

u=4 kmph

q= 5 min=1/12 hr

v= 5 kmph

After plugging the value you get the distance as 10/3 kms