Question

If a man travels at a speed of 30 km/h, he
reaches his destination 10 min late and if he
travels at a speed of 42 km/h, he reaches his
destination 10min early. The distance
travelled is​

Answer 1

Answer:

35 km

Step-by-step explanation:

Let the distance be y in km.  

Then, correct time at a speed of  

30 km / h = y/30 - 10/60

Correct time at a speed of 42 km /h  

= y/42 + 10/60

equating both equations

y/30 - 10/60 = y/42 + 10/60

y/30 - y/42 = 2/6

=> 72 y= 1260 × 2

=>  y = 35 km