Math, asked by shantikumari851201, 5 months ago

If a man travels at a speed of 30 km/h, he
reaches his destination 10 min late and if he
travels at a speed of 42 km/h, he reaches his
destination 10min early. The distance
travelled is.??????​

Answers

Answered by mgupta0751
13

speed=30*1000/60=500m/min

42*1000/60=700m/min

500(x+10)=700(x-10)

5x+50=7x-70

2x=120

x=60min

distance= speed*time

=500(60+10)

500*70=35000m

35km

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