Question

If a man travels at a speed of 30 km/hr, he
reaches his destination 10 minutes late and if
he travels at a speed of 42 km/hr, he reaches
his destination 10 minutes early. The distance
travelled is :​

Answer 1

Answer:

35

Step-by-step explanation:

Then, correct time at a speed of

30 km / h = x30 - 1060

Correct time at a speed of 42 km /h

= x42 + 1060

=> x30 - 1060 = x42 + 1060

=> x30 - x42 = 26

=> x(12)1260 = 26

=> 72 x = 1260 × 2

=> x = 1260×272 => x = 35 km

Answer 2

Answer:

35km

Step-by-step explanation:

if he travels in 30km/hr

speed = 30km/hr

time = x+10/60hr

if speed = 42km/hr

time = x-10/60hr

this problem is in inverse variation

30(x+10/60) = 42(x-10/60)

30x+5 = 42x-7

42x-30x = 5+7

12x = 12

x = 1

distance = speed*time

y = 30 (1+1/6)

  = 30 * 7/6

  =5*7

   =35km